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Set operators are very convenient when building new queries by combining the multiple query blocks you wrote (and tested) before, without writing completely new SQL code. This simplifies testing, because you have more control over correctness. Listing 8-44 answers the following question: Which locations host course offerings without having a department Listing 8-44. MINUS Set Operator Example SQL> select o.location from offerings o 2 MINUS 3 select d.location from departments d; LOCATION -------SEATTLE SQL> You can also try to solve this problem without using the MINUS operator. See Listing 8-45 for a suggestion. Listing 8-45. Alternative Solution Without Using the MINUS Operator SQL> select DISTINCT o.location 2 from offerings o 3 where o.location not in 4 (select d.location 5 from departments d) Note that you must add a DISTINCT operator, to handle situations where you have multiple course offerings in the same location. As explained before, the MINUS operator automatically removes duplicate rows. Are the two queries in Listing 8-44 and 8-45 logically equivalent Further investigations are left to the readers in one of the exercises at the end of this chapter. You can also produce outer join results by using the UNION operator. You will see how to do this in Listings 8-46 and 8-47. We start with a regular join in Listing 8-46. In Listing 8-47 you add the additional department(s) needed for the outer join with a UNION operator, while assigning the right number of employees for those departments: zero. Listing 8-46. Regular Join SQL> 2 3 4 5 6 select , , from , where d.deptno d.dname count(e.empno) as headcount employees e departments d e.deptno = d.deptno

your application. I think it would be really sweet and exciting to have Apple s implementation of GCD, blocks, and OpenCL on the iPhone at some point in the future possibly in the next version of the iPhone and iPhone OS at WWDC 2010! But concurrent solutions exist already so let s look at a possible use case without using concurrency and see how various concurrent solutions can increase user satisfaction and perhaps ease development efforts.

Listing 8-47. Expansion to an Outer Join with a UNION Operator SQL> 2 3 4 5 6 7 8 9 10 11 12 13 14 15 select , , from , where group by , union select , , from where d.deptno d.dname count(e.empno) as headcount employees e departments d e.deptno = d.deptno d.deptno d.dname x.deptno x.dname 0 as headcount departments x x.deptno not in (select y.deptno from employees y);

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Almost any long-running operation can make the user interface sluggish and unresponsive Some examples of operations that can impact the responsiveness of your user interface are loading images or data over the Internet to be displayed in your application; manipulating images or data; parsing XML or RSS; performing a complex mathematical calculation such as finding n prime numbers, calculating pi to m decimal places, or calculating Euler s constant e to p decimal places In addition, there are situations where a concurrent solution is typically used such as sorting a socket server as well as countless other situations As a point of discussion for looking at concurrent solutions, you will develop a simplistic application to view the images that have made it into Flickr s top 500 interestingness list for the most recent day.

The following exercises will help you to better understand the topics covered in this chapter The answers are presented in Appendix D 1 Produce an overview of all course offerings Provide the course code, begin date, course duration, and name of the trainer 2 Provide an overview, in two columns, showing the names of all employees who ever attended an SQL course, with the name of the trainer 3 For all employees, list their name, initials, and yearly salary (including bonus and commission) 4 For all course offerings, list the course code, begin date, and number of registrations Sort your results on the number of registrations, from high to low 5 List the course code, begin date, and number of registrations for all course offerings in 1999 with at least three registrations 6.

Schematically, your Interestingness app will make RESTful HTTP requests to Flickr servers and receive a response in JavaScript Object Notation (JSON) a lightweight data format for transferring data in name value pairs (see Figure 1 1) The images will be displayed using a UITableView managed by a UITableViewController Interestingness is a ranking assigned to each photo using a secret algorithm patented by Flickr based on a number of factors including the number of users who added the photo to a list of favorites, origin of the clickthroughs, user assigned tags, comments, relationship between the uploader of the image and those who comment on the image, and other secret factors Flickr s flickrinterestingnessgetList API is used to retrieve this list and does not require user authentication only an API key.

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