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46. What does DAT stand for A. Diagnostic Audio Transceiver B. Digital Audio Tape C. Digital Analog Tape D. Diagnostic Analog Tap 47. When adding memory to a server, what should be the first item to check before ordering additional RAM A. Make sure it is the same brand as the current RAM. B. Check for an available memory slot. C. Upgrade the system BIOS. D. Run a memory check on the current RAM. 48. To gain maximum performance from your backup tape drive, which of the following can a technician do A. Use a cleaning tape regularly B. Use DAT tapes C. Use a toothbrush to clean the heads of the tape drive D. Replace the tape drive every 12 months 49. What is SNMP A. A video bus technology B. The method of using dual processors in a system C. A network protocol for routing information D. A protocol used to measure various system attributes 50. After a new server is installed, the technician notices that the NIC on the newly installed server is not functioning properly. What is the most likely cause of the problem A. The technician did not verify hardware requirements. B. The technician did not get the latest drivers from the manufacturer. C. The technician did not flash the BIOS to recognize the NIC. D. The technician forgot to enable plug-and-play capabilities on the new server. 51. What does the term multiprocessing mean A. Running a system that has two or more database files installed. B. A database can be updated by several users at the same time. C. Running a system with more than one processor. D. Able to connect two or more monitors to the server.

(2.5) (2.5)

100 90 80 (%) Penetration 70 60 50 40 30 20 10 0 2002 2003 2004 US 2005 2006 2007 Korea 2008 2009 2010 Europe UK

We see immediately from Eq. (B.17) that v2 v3. Hence, from Eqs. (B.19) and (B.20) it follows that i2 2i3. Then Eq. (B.15) can be rewritten as i1 3i3 0 Combining Eqs. (B.18) and (B.19) with Eq. (B.16) and using i2 2i3 yield 12 2i1 6i3 0 Subtracting two times Eq. (B.21) from Eq. (B.22) yields 12 4i1 0 and we have i1 3. From Eq. (B.21) follows i3 1 and, hence, that i2 2. In summary, we have i1 3 A, i2 2 A, i3 1 A, v1 v2 v3 6 V. B B:22 B:21

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such entrance point, from which intelligent ooding can be initiated to reach the connected nodes inside the region Let R be the transmission radius, assumed identical for every node It can be observed that any entrance point is necessarily (by de nition) at a distance R from the region border It is then possible to reach all entrance points by using geographic multicasting to well chosen areas around the region These locations, called entrance zones, must be determined such that: 1 Any entrance point necessarily belongs to an entrance zone, which implies that the union of all entrance zones must surround the region with a width larger than R 2 If a node inside any zone retransmits a message, then any other node inside the same zone must receive it.

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This property ensures the possibility to reach all potential entry points in a zone from any of the nodes in it The associated requirement is that entrance zones must have a diameter smaller than R As illustrated in Figure 510, these two constraints cannot be respected together if a single layer of zones is considered (both measures in Fig 510a are incompatible) The exact construction of entrance zones to satisfy these criteria actually depends on the shape of the geocasting region If the geocasting region is a rectangle, for example, then the entrance zones may be composed of two layers of squares of length R/2, or better, composed of rectangles where one dimension (the one perpendicular to the region) is R/2 and the other dimension is as large as possible, provided the zone s diameter does not exceed R (as illustrated in Fig 510b).

Another example that considers a circular geocasting region is provided in Stojmenovic and Wu (2006) Once all entrance zones are determined by the source, a geographical multicast task is initiated from the source toward the centers of all zones using a.

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