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class RefDemo { public static void main(String args[]) { BoxWeight weightbox = new BoxWeight(3, 5, 7, 837); Box plainbox = new Box(); double vol; vol = weightboxvolume(); Systemoutprintln("Volume of weightbox is " + vol); Systemoutprintln("Weight of weightbox is " + weightboxweight); Systemoutprintln(); // assign BoxWeight reference to Box reference plainbox = weightbox; vol = plainboxvolume(); // OK, volume() defined in Box Systemoutprintln("Volume of plainbox is " + vol); /* The following statement is invalid because plainbox does not define a weight member */ // Systemoutprintln("Weight of plainbox is " + plainboxweight); } } Here, weightbox is a reference to BoxWeight objects, and plainbox is a reference to Box objects Since BoxWeight is a subclass of Box, it is permissible to assign plainbox a reference to the weightbox object It is important to understand that it is the type of the reference variable not the type of the object that it refers to that determines what members can be accessed That is, when a reference to a subclass object is assigned to a superclass reference variable, you will have access only to those parts of the object defined by the superclass This is why plainbox can't access weight even when it refers to a BoxWeight object If you think about it, this makes sense, because the superclass has no knowledge of what a subclass adds to it This is why the last line of code in the preceding fragment is commented out It is not possible for a Box reference to access the weight field, because it does not define one Although the preceding may seem a bit esoteric, it has some important practical applications two of which are discussed later in this chapter

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In the preceding examples, classes derived from Box were not implemented as efficiently or as robustly as they could have been For example, the constructor for BoxWeight explicitly initializes the width, height, and depth fields of Box( ) Not only does this duplicate code found in its superclass, which is inefficient, but it implies that a subclass must be granted access to these members However, there will be times when you will want to create a superclass that keeps the details of its implementation to itself (that is, that keeps its data members private) In this case, there would be no way for a subclass to directly access or initialize these variables on its own Since encapsulation is a primary attribute of OOP, it is not surprising that Java provides a solution to this problem Whenever a subclass needs to refer to its immediate superclass, it can do so by use of the keyword super super has two general forms The first calls the superclass' constructor The second is used to access a member of the superclass that has been hidden by a member of a subclass Each use is examined here

1114 For a particular binary liquid solution at constant T and P, the molar enthalpies of mixtures are represented by the equation:

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3:

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where the ai and bi are constants Since the equation has the form of Eq (111 I), it might be that = ai bixi Show whether this is true

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A subclass can call a constructor method defined by its superclass by use of the following form of super: super(parameter-list); Here, parameter-list specifies any parameters needed by the constructor in the superclass super( ) must always be the first statement executed inside a subclass' constructor To see how super( ) is used, consider this improved version of the BoxWeight( ) class: // BoxWeight now uses super to initialize its Box attributes class BoxWeight extends Box { double weight; // weight of box // initialize width, height, and depth using super() BoxWeight(double w, double h, double d, double m) { super(w, h, d); // call superclass constructor weight = m; }

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Mi are related by the equation:

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