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Pay careful attention to the declaration Notice that the two dimensions are separated from each other by a comma In the first part of the declaration, the syntax

// One interface can inherit another using System; public interface IA { void Meth1(); void Meth2(); }

indicates that a two-dimensional array reference variable is being created When memory is actually allocated for the array using new, this syntax is used:

There is only one exception: The verb to be requires the use of who regardless of where it appears in the sentence For example, in analyzing whether to replace him (or her) with who or whom in the following sentence, use the three-step model:

// IB now includes Meth1() and Meth2() -- it adds Meth3() public interface IB : IA { IB inherits IA void Meth3(); } // This class must implement all of IA and IB class MyClass : IB { public void Meth1() { ConsoleWriteLine("Implement Meth1()"); } public void Meth2() { ConsoleWriteLine("Implement Meth2()"); } public void Meth3() { ConsoleWriteLine("Implement Meth3()"); } } class IFExtend { static void Main() { MyClass ob = new MyClass(); obMeth1(); obMeth2(); obMeth3(); } }

int[10, 20]

Part I:

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As an experiment, you might want to try removing the implementation for Meth1( ) in MyClass This will cause a compile-time error As stated earlier, any class that implements an interface must implement all methods defined by that interface, including any that are inherited from other interfaces

To access an element in a two-dimensional array, you must specify both indices, separating the two with a comma For example, to assign the value 10 to location 3, 5 of array table, you would use

table[3, 5] = 10;

Q: A:

Here is a complete example It loads a two-dimensional array with the numbers 1 through 12 and then displays the contents of the array

// Demonstrate a two-dimensional array using System; class TwoD { static void Main() { int t, i; int[,] table = new int[3, 4]; for(t=0; t < 3; ++t) { for(i=0; i < 4; ++i) { table[t,i] = (t*4)+i+1; ConsoleWrite(table[t,i] + " "); } ConsoleWriteLine(); } } }

When one interface inherits another, is it possible to declare a member in the derived interface that hides a member defined by the base interface Yes When a member in a derived interface has the same signature as one in the base interface, the base interface name is hidden As is the case with class inheritance, this hiding will cause a warning message, unless you specify the derived interface member with new

In this example, table[0, 0] will have the value 1, table[0, 1] the value 2, table[0, 2] the value 3, and so on The value of table[2, 3] will be 12 Conceptually, the array will look like the one shown in Figure 7-1

When implementing a member of an interface, it is possible to fully qualify its name with its interface name Doing this creates an explicit interface member implementation, or explicit implementation, for short For example, given

multidimensional arrays in C# In these other languages, array dimensions and indices are specified within their own set of brackets C# separates dimensions using commas

I know him (or her )

C# allows arrays with more than two dimensions Here is the general form of a multidimensional array declaration: type[, ,] name = new type[size1, size2, , sizeN];

interface IMyIF { int MyMeth(int x); }

7:

For example, the following declaration creates a 4 10 3 three-dimensional integer array:

it is legal to implement IMyIF as shown here:

int[,,] multidim = new int[4, 10, 3];

class MyClass : IMyIF { int IMyIFMyMeth(int x) { return x / 3; } }

To assign element 2, 4, 1 of multidim the value 100, use this statement:

multidim[2, 4, 1] = 100;

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