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triangle. The voltage is E, the current is I, and the resistance is R. These quantities are expressed in volts, amperes, and ohms, respectively.

5 1. B 5. A 9. B 13. B 17. B 2. D 6. B 10. D 14. C 18. C 3. C 7. D 11. B 15. A 19. B 4. C 8. A 12. C 16. C 20. C

This is the fundamental transmission rate of the SONET STS-1 frame. That s a lot of bandwidth. 51.84 Mbps is slightly more than a 44.736 Mbps DS-3, a respectable carrier level by anyone s standard. What if more bandwidth is required, however What if the user wants to transmit multiple DS-3s, or perhaps a single signal that requires more than 51.84 Mbps, such as a 100-Mbps Fast Ethernet signal Or for that matter, a payload that requires less than 51.84 Mbps. In those cases, we have to invoke more of SONET s magic.

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Remember that you must use units of volts, amperes, and ohms for the Ohm s Law formulas to yield a meaningful result! If you use, say, volts and microamperes to calculate a resistance, you cannot be sure of the units you ll end up with when you derive the final result. If the initial quantities are given in units other than volts, amperes, and ohms, convert to these units, and then calculate. After that, you can convert the calculated current, voltage, or resistance value to whatever size unit you want. For example, if you get 13,500,000 as a calculated resistance, you might prefer to say that it s 13.5 M .

3. 7. 11. 15. 19.

In situations where multiple STS-1s are required to transport multiple payloads, all of which fit in an STS-1 s payload capacity, SONET enables the creation of what are called STS-N frames, where N represents the number of STS-1 frames that are multiplexed together to create the frame. If three STS-1s are combined, the result is an STS-3. In this case, the three STS-1s are brought into the multiplexer and byte interleaved to create the STS-3, as shown in Figure 3-62. In other words, the multiplexer selects the first byte of frame one, followed by the first byte of frame two, followed by the first byte of frame three. Then it selects the second byte of frame one, followed by the second byte of frame two, followed by the second byte of frame three, and so on, until it has built an interleaved frame that is now three times the size of an STS-1: 9 270 bytes instead of 9 90. Interestingly (and impressively), the STS-3 is still generated 8,000 times per second.

4. 8. 12. 16. 20.

The first way to use Ohm s Law is to determine current in dc circuits. In order to find the current, you must know the voltage and the resistance, or be able to deduce them. Refer to the schematic diagram of Fig. 4-7. It consists of a dc voltage source, a voltmeter, some wire, an ammeter, and a calibrated, wide-range potentiometer.

3. 7. 11. 15. 19.

Problem 4-1 Suppose that the dc generator in Fig. 4-7 produces 10 V and the potentiometer is set to a value of 10 . What is the current This is solved by the formula I = E/R. Plug in the values for E and R; they are both 10, because the units are given in volts and ohms. Then I = 10/10 = 1.0 A. Problem 4-2 Imagine that dc generator in Fig. 4-7 produces 100 V and the potentiometer is set to 10 k . What is the current First, convert the resistance to ohms: 10 k = 10,000 . Then plug the values in: I = 100/10,000 = 0.01 A. You might prefer to express this as 10 mA. Problem 4-3 Suppose that dc generator in Fig. 4-7 is set to provide 88.5 V, and the potentiometer is set to 477 M . What is the current This problem involves numbers that aren t exactly round, and one of them is huge. But you can use a calculator. First, change the resistance value to ohms, so you get 477,000,000 . Then plug into the Ohm s Law formula: I = E/R = 88.5 / 477,000,000 = 0.000000186 A. It is more reasonable to express this as 0.186 A or 186 nA.

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4. 8. 12. 16. 20.

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