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If no download is selected in the downloads table, all of the buttons are disabled, giving them a grayed-out appearance. However, if there is a selected download, each button s state will be set based on whether the Download object has a status of DOWNLOADING, PAUSED, ERROR, COMPLETE, or CANCELLED.

" Keep in mind that VN denotes the voltage drop from the junction point in the load to the junction point at O. Therefore, since the generator voltage is equal to the sum of the voltage drops in any closed path, we have the following three voltage equations in Fig. 267: " " " V Z A IA V N " " " " aV ZB IB VN " " " " a2 V ZC IC VN Here we re dealing with the general case of unequal load impedances; thus the three line (and phase) currents will, in general, be unequal, and hence can be resolved into the sum of positive and negative sequences; thus " " " IA IA1 IA2 " " " IB IB1 IB2 " " " IC IC1 IC2

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which, upon making use of eqs. (461), (462), (464), and (465), can also be written as " " " IA IA1 IA2 " "" " " IB aIA1 a2 IA2 " " " "" IC a2 IA1 aIA2 " " " and thus, upon substituting these values of IA , IB , and IC into the rst set of equations following Fig. 267, you should nd that " " " " " ZA IA1 ZA IA2 VN V " "" " " " " " aZB IA1 a2 ZB IA2 VN aV " "" " " " " " a2 ZC IA1 aZC IA2 VN a2 V 468 469 470

Each of DownloadManager s GUI controls registers an ActionListener that invokes its respective action method. ActionListeners are triggered each time an action event takes place on a GUI control. For example, when a button is clicked, an ActionEvent is generated and each of the button s registered ActionListeners are notified. You may have noticed a similarity between the way ActionListeners work and the Observer pattern discussed earlier. That is because they are the same pattern with two different naming schemes.

Problem 215 Here you are asked to complete the foregoing discussion concerning Fig. 267 as follows. Making use of eqs. (460) and (463), and the fact that, by Kirchho s current " " " law, IA IB IC 0, show that the values of the line currents in Fig. 267 are given by the equations " " " " 1:732 YA YC j30 YA YB j30 V " IA " " "A YB YC Y " " " " 1:732 YB YC j90 YA YB j30 V " IB " " " YA YB YC " " " " 1:732 YA YC j30 YB YC j90 V " IC " " " YA YB YC where, in terms of the admittances " " YA 1=ZA " " YB 1=ZB " " YC 1=ZC 471 472 473

in which the reciprocal ohms are called mhos. Problem 216 " " " In Fig. 267 let V 125 volts, ZA 3 j4 ohms, ZB 8 ohms, and ZC 5 ohms. Using symmetrical components, verify that the magnitudes of the line currents, in amperes, are equal to " jIA j 25:99 " jIB j 22:85 " jIC j 17:37

Compile DownloadManager like this:

Problem 217 In three-phase work we often deal in terms of line voltage instead of phase voltage. Thus, in Fig. 267, suppose that the reference voltage is taken to be the " line voltage, VAB VAB =08 VAB , this being the voltage from the center wire to the top wire in the diagram. What changes would be required to express eqs. (471) through (473) in terms of line voltage instead of phase voltage

It should be noted that the three-phase problems we ve solved here, using the method of symmetrical components, could also have been solved by the ordinary method of loop currents. It should, however, also be noted that other types of three-phase problems exist in which application of the method of symmetrical components provides the only practical way of obtaining exact and rigorous solutions.

Run DownloadManager like this:

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