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// Store values in third array for(i=0; i < 5; i++) jagged[2][i] = i; // Display values in first array for(i=0; i < 4; i++) ConsoleWrite(jagged[0][i] + " "); ConsoleWriteLine(); // Display values in second array for(i=0; i < 3; i++) ConsoleWrite(jagged[1][i] + " "); ConsoleWriteLine(); // Display values in third array for(i=0; i < 5; i++) ConsoleWrite(jagged[2][i] + " "); ConsoleWriteLine(); } }

The output is shown here:

As you can see, when the MyMeth( ) member of IMyIF is implemented, its complete name, including its interface name, is specified There are two reasons that you might need to create an explicit implementation of an interface member First, it is possible for a class to implement two interfaces, which both declare methods by the same name and type signature Qualifying the names with their interfaces removes the ambiguity from this situation Second, when you implement a method using its fully qualified name, you are providing an implementation that cannot be accessed through an object of the class Thus, an explicit implementation gives you a way to implement an interface method so that it is not a public member of the implementing class Let s look at an example of each The following program contains an interface called IEven, which defines two methods, IsEven( ) and IsOdd( ) These methods determine whether a number is even or odd MyClass then implements IEven When it does so, it implements IsOdd( ) explicitly

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0 1 2 3 0 1 2 0 1 2 3 4

1 The verb is am 2 The subject is I 3 The word he (or she) is not the subject of the sentence; therefore, it would seem to be correct to use whom However, the word am is a form of the verb to be and as such is the exception to the rule Thus it is correct to write:

// Explicitly implement an interface member using System; interface IEven { bool IsOdd(int x); bool IsEven(int x); } class MyClass : IEven { // Explicit implementation bool IEvenIsOdd(int x) { if((x%2) != 0) return true; else return false; }

Jagged arrays are not used by all applications, but they can be effective in some situations For example, if you need a very large two-dimensional array that is sparsely populated (that is, one in which not all of the elements will be used), then a jagged array might be a perfect solution One last point: Because jagged arrays are arrays of arrays, there is no restriction that requires that the arrays be one-dimensional For example, the following creates an array of two-dimensional arrays:

int[][,] jagged = new int[3][,];

Explicitly implement IsOdd( )

The next statement assigns jagged[0] a reference to a 4 2 array:

jagged[0] = new int[4, 2];

// Normal implementation public bool IsEven(int x) { IEven o = this; // Interface reference to invoking object return !oIsOdd(x); } } class Demo { static void Main() { MyClass ob = new MyClass(); bool result; result = obIsEven(4); if(result) ConsoleWriteLine("4 is even"); else ConsoleWriteLine("3 is odd"); // result = obIsOdd(); // Error, not exposed } }

The following statement assigns a value to jagged[0][1,0]:

jagged[0][1,0] = i;

Since IsOdd( ) is implemented explicitly, it is not exposed as a public member of MyClass Instead, IsOdd( ) can be accessed only through an interface reference This is why it is invoked through o in the implementation for IsEven( ) Here is an example in which two interfaces are implemented and both interfaces declare a method called Meth( ) Explicit implementation is used to eliminate the ambiguity inherent in this situation

As with other objects, when you assign one array reference variable to another, you are simply making both variables refer to the same array You are neither causing a copy of the

// Use explicit implementation to remove ambiguity using System; interface IMyIF_A { int Meth(int x); } interface IMyIF_B { int Meth(int x); } // MyClass implements both interfaces class MyClass : IMyIF_A, IMyIF_B { IMyIF_A a_ob; IMyIF_B b_ob; // Explicitly implement the two Meth()s Explicit implementation removes the ambiguity int IMyIF_AMeth(int x) { return x + x; }

7:

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