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Description Writes the information specified by info to the URI specified by uri The response is returned The string passed in how specifies how the information will be written Writes the information in the file specified by fname to the URI specified by uri The response is returned Writes the information in the file specified by fname to the URI specified by uri The response is returned Writes the information in the file specified by fname to the URI specified by uri The response is returned The string passed in how specifies how the information will be written Writes the information in the file specified by fname to the URI specified by uri The response is returned The string passed in how specifies how the information will be written Writes str to the URI specified by uri The response is returned Writes str to the URI specified by uri.

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The coefficientsyielding the minimum sum of the squares the residuals obtainedby of are settingthe partial derivativesequal to zero and expressing resultin matrix form as the

The response is returned Writes str to the URI specified by uri The response is returned The string passed in how specifies how the information will be written Writes str to the URI specified by uri The response is returned The string passed in how specifies how the information will be written Writes the values in the collection specified by vals to the URI specified by uri The response is returned Writes the values in the collection specified by vals to the URI specified by uri The response is returned Writes the values in the collection specified by vals to the URI specified by uri The response is returned The string passed in how specifies how the information will be written Writes the values in the collection specified by vals to the URI specified by uri The response is returned.

How can we handle the uctuations in demand There are three ways: 1. Overtime, but this is expensive since overtime pay is 80% more than regular pay. Also, workers can put in at most 30% overtime. 2. Hiring and ring, but these cost $320 and $400, respectively, per worker. 3. Storing surplus production, but this costs $8 per carpet per month. We currently have no stored carpets on hand, and we must end the year without any carpets stored. This rather involved problem can be formulated and solved as a linear program! A crucial rst step is de ning the variables. wi = number of workers during ith month; w 0 = 30. xi = number of carpets made during ith month. oi = number of carpets made by overtime in month i. hi , fi = number of workers hired and red, respectively, at beginning of month i. si = number of carpets stored at end of month i; s 0 = 0. All in all, there are 72 variables (74 if you count w 0 and s0 ). We now write the constraints. First, all variables must be nonnegative: wi , xi , oi , hi , fi , si 0, i = 1, . . . , 12. The total number of carpets made per month consists of regular production plus overtime: xi = 20wi + oi (one constraint for each i = 1, . . . , 12). The number of workers can potentially change at the start of each month: wi = wi 1 + hi fi .

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The string passed in how specifies how the information will be written..

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The QUICKCALC command allows you to perform a full range of mathematical and trigonometric calculations, as well as determine graphic information such as the location of a point or the length of a line. 1. Select the Open button from the Quick Access toolbar and open the deck.dwg le. 2. Pick the QuickCalc button from the Utilities panel, or type QUICKCALC at the keyboard.

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