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Since they are composed of lymphatic tissue, these ve tonsils play minor roles in body defense. They contain lymphocytes and macrophages that phagocytose foreign invaders entering the nose, mouth, or throat. These invaders naturally include various airborne bacteria and viruses. Sometimes, however, the lymphatic tissue of the tonsils becomes overwhelmed by a huge number of bacteria or viruses. In such cases, tonsillitis (tahn-sihl-EYE-tis) may result. Tonsillitis is an in ammation and swelling of (-itis) the tonsils. This in ammation may be accompanied by a dangerously high fever. The operation of tonsillectomy (tahn-sihl-EK-toh-mee) or removal of (-ectomy) the tonsils is then frequently performed. [Study suggestion: Using your growing knowledge, write a single term that literally means, in ammation of the adenoids. Why do you think that a person a icted with this condition might have trouble breathing ]

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( w h e r e : : a l l i t u c l ( r n )a h i l v ct h cc a r t h ' s u d : r c ed c t ] n c d s : : 0 ) l o : t h c i n i t i a lt l t i t u c l e e s a ( m ) ,l r : r n i l s sk g ) ,( : a l i n c a r d r a g o e l ' l ' i c i c( ktg / s ) , r : i n i t i ' r lv c l o c i t y r n / s )a n dI : ( q ( , c n (s).

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Now we have the following data:

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If each row of H is denoted as hi , then the rst three components of each hi de ne a unit vector pointing from the satellite to the point of linearization xk . For each iteration of eqn. (8.10), the matrix H should be recalculated. This recalculation is most important when pk p is large. The iteration of eqn. (8.10) assumes that the rows of H are linearly independent so that the required matrix inverse exists. The iteration of eqn. (8.10) is concluded when the change in the estimate xk given by 1 H ( ( k )) x (8.13) dxk = H H in a given iteration has magnitude dxk less than a prespeci ed threshold. The fact that dxk is small at the conclusion of the iteration does not imply that (8.14) xk = x xk is small. The estimate xk was selected to minimize the norm of the error between the computed pseudorange and measurements of the pseudorange. Therefore, the pseudorange measurement errors de ned in eqn. (8.7)

s ri ' A t d i s p l a y c d i n F i g T l , t h c j u r n p c r r i s c s t o a p c a k c l c v a t i o n1 9'0rn ro u a h o u t l : - 1s ol i b at l S u p p o s t h a ty o u a r cg i v c nt h c - j o h l ' d c t c r r r i n i ntg ce x l c t l i r n eo l ' t h cp c a kc l c v a l i o n .

replace the arbitrary network shown in Fig. 10-1 with the simple network shown in Fig. 10-2. Now let s determine the power absorbed by the load. It s easy to show that, given the circuit shown in Fig. 10-2, the power delivered to the load is PL = I 2 R L = VTH RTH + R L

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