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'' add font and size formatting strText = "\Fromand.shx;\H0.5;" & strText '' create the mtext Set objEnt = ThisDrawing.ModelSpace.AddMText(varStart, dblWidth, strText) objEnt.Update End Sub Rich text format (RTF) control codes aren t recognized in an MText entity. Text from other programs with embedded formatting will lose that formatting when you import it into an MText-style paragraph if you re working with AutoCAD 2000, 2000i, or 2002. Formatting is well preserved within AutoCAD 2004 and higher, however. You can paste Microsoft Word documents directly into AutoCAD 2002 and higher as MText and maintain their original formatting. AutoCAD 2000, 2000i, and 2002 exhibit odd behavior with respect to exploding block insertions that contain MText entities. In these versions, the nested MText entities are automatically exploded into individual Text entities when you use the VBA Explode method. This doesn t occur in AutoCAD 2004 and higher, however, and MText is preserved after the Explode method is executed. Text styles may be applied similarly to normal Text objects. 2005 and 2006 allows you to retrieve the field codes used to display special characters within the text string. However, the special codes inserted using an AutoCAD command may not be retrieved. A good rule of thumb is, if you can add a code programmatically, then you can retrieve it as well.

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Substituting 8 for y and 1 for x in y = 48x + b, we have 2 8 = 48 Thus, the equation is y = 48x + 32. 1 +b 2 or 8 = 24 + b or b = 32

(d) The required graph is shown in the adjoining Fig. 4-8. Note that the slopes of the lines y x and y x are 1 and 1 respectively, representing the right and left hand derivatives at x 0. However, the derivative at x 0 does not exist.

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13.6 Find the derivatives of the functions de ned by the following formulas: x2 3 (b) (a) (x 100 + 2x 50 3)(7x 8 + 20x + 5) x+4 4 2 3 (e) 8x 3 x 2 + 5 + 3 (d) 5 x x x (c) (f ) x5 x + 2 x3 + 7 3x 7 + x 5 2x 4 + x 3 x4

4.8. Prove that f x x2 is di erentiable in 0 @ x @ 1.

Let x0 be any value such that 0 < x0 < 1. f 0 x0 lim At the end point x 0,

Find the slope-intercept equation of the tangent line to the graph of the function at the indicated point: 1 x+2 , at x = 1 (a) f (x) = 2 , at x = 2 (b) f (x) = 3 x x 1 Let f (x) = x+2 for all x = 2. Find f ( 2). x 2

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Point objects can act as nodes to which you can snap objects. You can specify a full 3-D WCS location for a point. You use the AddPoint method to create a new Point object, as follows: Set PointObject = Object.AddPoint(PointPosition) Table 8-15 provides a brief description of the PointPosition argument. Table 8-15. AddPoint Method Parameter

h!0

13.8 13.9

At the end point x 1,

13.10 The parabola in Fig. 13-2 is the graph of the function f (x) = x 2 4x. (a) Draw the graph of y = | f (x)|. (b) Where does the derivative of | f (x)| fail to exist

h!0

Fig. 13-2

Controlling How a Point Object Is Displayed The appearance of Point objects is controlled by the system variables PDMODE and PDSIZE. The PDMODE variable specifies the figure used to represent a point. This variable may take a value from 0 to 4, as Figure 8-12 illustrates. A value of 1 means that nothing is displayed. You can combine the PDMODE variable value with the number 32, 64, or 96, which represents a surrounding shape. Figure 8-13 shows the possible combined symbols for a Point object. The PDSIZE variable controls the size of the Point object figure. It has no effect if you set PDMODE to 0 or 1. You may set PDSIZE to a positive, negative, or zero value:

Then f x is di erentiable in 0 @ x @ 1. We may write f 0 x 2x for any x in this interval. 0 0 customary to write f 0 f 0 0 and f 1 f 0 1 in this case.

13.11 GC Use a graphing calculator to nd the discontinuities of the derivatives of the following functions: (a) f (x) = x 2/3 (b) f (x) = 4 |x 2| + 3 (c) f (x) = 2 x 1 13.12 Evaluate lim 1 1 1 . (1 + h)8

0 0 0

14.1 RELATIVE EXTREMA A function f is said to have a relative maximum at x = c if f (x) f (c) for all x near c. More precisely, f achieves a relative maximum at c if there exists > 0 such that |x c| < implies f (x) f (c). EXAMPLE For the function f whose graph is shown in Fig. 14-1, relative maxima occur at x = c1 and x = c2 . This is obvious,

(a) x 1=3;

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